yes it is. the correct way to do it is via either union type punning, or memcpy()

this is technically UB

Wow, I did not know the function count.

I still do not understand when to use .count ... baaackk to W3schools

cool

The most common math mistake of all time - the minus sign.

Jokes aside, fixed.

There seems to still be an error in the expected solution:

For n == 3:
'sin(3 * x)  ==  3 cos(x)^2 sin(x) - sin(x)^3' should equal 'sin(-3 * x)  ==  3 cos(x)^2 sin(x) - sin(x)^3'

My bad, fixed. Small mistake in the solution has occured.

This particular random test seems to not want the sin(-5 * x) == part of the expression:

'sin(-5 * x)  ==  - 5 cos(x)^4 sin(x) + 10 cos(x)^2 sin(x)^3 - sin(x)^5' should equal '- 5 cos(x)^4 sin(x) + 10 cos(x)^2 sin(x)^3 - sin(x)^5'

It's not consistent because other random tests do require that prefix.

Fixed it!

Fixed it!

Before you publish your challenge: this solution passes all tests:

def decode_void_whispers(message):
    
    # Your implementation here
    pass

There, fixed!

Hey guys, I'm still finishing authoring this, sorry!