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Andrew5057vs.seraph776

uwu

Code
Diff
  • def bool_to_word(param):  
    return ("No", "Yes")[param]
    • def bool_to_word(param):
    • return {True: "Yes", False: "No"}[param]
    • return ("No", "Yes")[param]
Andrew5057vs.seraph776

Find maximum number that can be formed using digits of a given number

Code
Diff
  • class MaxDigit:
    def __init__(self, n):
        self.n = n

    def execute(self):
        return sum(10**i * int(n) for i, n in enumerate(sorted(str(self.n))))
    • class MaxDigit:
    • def __init__(self, n):
    • self.n = n
    • def execute(self):
    • return int(''.join((sorted([n for n in str(self.n)], reverse=True))))
    • return sum(10**i * int(n) for i, n in enumerate(sorted(str(self.n))))
Andrew5057vs.Echo1995

Joker_04's Kumite #2

Code
Diff
  • import random

def sum_of_numbers(a, b):
    if random.random() < 0.01:
        return a + b
    else:
        return sum_of_numbers(a, b)
    • import random
    • def sum_of_numbers(a, b):
    • return b + a
    • if random.random() < 0.01:
    • return a + b
    • else:
    • return sum_of_numbers(a, b)
Andrew5057vs.user6600331

Make It Greater Than 2

Code
Diff
  • #If it is not true currently, I shall make it true
def above_two(arg):
    arg = 3
    return arg > 2
    • #If it is not true currently, I shall make it true
    • def above_two(arg):
    • if not(arg > 2):
    • while not(arg > 2):
    • arg += 1
    • return True
    • pass
    • else:
    • return True
    • arg = 3
    • return arg > 2
Andrew5057vs.williambastard

Prebrojavanje samoglasnika

Code
Diff
  • import re

pattern = re.compile(r"[aeiouyAEIOUY]")

def count(text: str) -> int:
    return len(re.findall(pattern, text))
    • import re
    • def count(text: str) -> int:
    • pattern = r"[aeiouyAEIOUY]"
    • # Find all vowel matches in the string/text
    • matches = re.findall(pattern, text)
    • pattern = re.compile(r"[aeiouyAEIOUY]")
    • # Return the number of vowels
    • return len(matches)
    • def count(text: str) -> int:
    • return len(re.findall(pattern, text))
Andrew5057vs.coolcoder7892

Multiply and Add One

Code
Diff
  • def multiply_and_add_one(a, b):
    return a * b + 1
    • def multiply_and_add_one(a, b):
    • r = a * b
    • return r + 1
    • return a * b + 1