This is smart move to consider the total sum of elements, but what if we have different numbers and their multiplicity while the sum is the same ? Is it possible ?

Ok, I just learned items of a list don't need to be ordered the same way to make an evaluation between 2 arrays.
(This will be invalid in PHP)

A solution that needs space proportional to the input numbers' values won't be able to handle the random tests.

• python new test frameworks to be used
• missing useful imports

Approved

python new test framework is required. updated in this fork

Author solution fails for test cases such as

m = [[0, 1, 0], 
     [0, 0, 0], 
     [0, 0, 1]]
test.assert_equals(solve(m), [1, 1])

Your post was visible in the homepage too for people who hasn't solved the kata yet.

I'm responding to a comment on the actual answer, so I don't understand how I'm spoiling anything?

Ivsz, use spoiler flag next time please.

this is the best one imo

No random tests.